Verify that 1/2, 1 and −2 are the zeroes of the cubic polynomial f(x) = 2x³ + x² − 5x + 2 and verify the relationship between the zeroes and coefficients
Video Explanation
Watch the video explanation below:
Given
f(x) = 2x³ + x² − 5x + 2
The given zeroes are:
1/2, 1 and −2
To Verify
- That the given numbers are zeroes of f(x)
- The relationship between zeroes and coefficients
Solution
Step 1: Verify the Zeroes
(i) f(1/2)
f(1/2) = 2(1/2)³ + (1/2)² − 5(1/2) + 2
= 2(1/8) + 1/4 − 5/2 + 2
= 1/4 + 1/4 − 5/2 + 2
= 1/2 − 5/2 + 2 = 0
∴ 1/2 is a zero of f(x).
(ii) f(1)
f(1) = 2(1)³ + (1)² − 5(1) + 2
= 2 + 1 − 5 + 2 = 0
∴ 1 is a zero of f(x).
(iii) f(−2)
f(−2) = 2(−2)³ + (−2)² − 5(−2) + 2
= −16 + 4 + 10 + 2 = 0
∴ −2 is a zero of f(x).
Hence, the given numbers are verified as zeroes of the polynomial.
Step 2: Verify Relationship Between Zeroes and Coefficients
For a cubic polynomial ax³ + bx² + cx + d:
Sum of zeroes = −b/a
Sum of product of zeroes taken two at a time = c/a
Product of zeroes = −d/a
Here, a = 2, b = 1, c = −5, d = 2
(i) Sum of Zeroes
1/2 + 1 + (−2) = −1/2
−b/a = −1/2
✔ Verified
(ii) Sum of Products of Zeroes Taken Two at a Time
(1/2 × 1) + (1 × −2) + (−2 × 1/2)
= 1/2 − 2 − 1 = −5/2
c/a = −5/2
✔ Verified
(iii) Product of Zeroes
(1/2) × 1 × (−2) = −1
−d/a = −2/2 = −1
✔ Verified
Final Answer
The given numbers 1/2, 1 and −2 are the zeroes of the polynomial f(x) = 2x³ + x² − 5x + 2.
The relationship between zeroes and coefficients is verified.
Conclusion
Thus, the cubic polynomial satisfies all standard relationships between its zeroes and coefficients.