Graphical Solution of a Pair of Linear Equations
Video Explanation
Question
Solve the following system of equations graphically:
\[ 2x + 3y = 4 \]
\[ x – y + 3 = 0 \]
Solution
Step 1: Write Both Equations in a Convenient Form
Equation (1):
\[ 2x + 3y = 4 \Rightarrow 3y = 4 – 2x \Rightarrow y = \frac{4 – 2x}{3} \]
Equation (2):
\[ x – y + 3 = 0 \Rightarrow y = x + 3 \]
Step 2: Prepare Table of Values
For Equation (1): \(2x + 3y = 4\)
| x | y |
|---|---|
| 2 | 0 |
| -1 | 2 |
For Equation (2): \(x – y + 3 = 0\)
| x | y |
|---|---|
| 0 | 3 |
| -1 | 2 |
Step 3: Graphical Representation
Plot the following points on the same Cartesian plane:
- Line 1: (2, 0) and (−1, 2)
- Line 2: (0, 3) and (−1, 2)
Join each pair of points to obtain two straight lines.
The two lines intersect at the point:
\[ (-1,\,2) \]
Conclusion
The graphical solution of the given system of equations is:
\[ \boxed{x = -1,\; y = 2} \]
Hence, the two lines intersect at the point (−1, 2).