Finding Stake Money of Two Cock Owners
Video Explanation
Question
A wizard makes offers to two cock owners. To one: if he wins, the wizard takes his stake; if he loses, the wizard pays \( \frac{2}{3} \) of the stake. To the other: if he wins, the wizard takes his stake; if he loses, the wizard pays \( \frac{3}{4} \) of the stake. In either case, the wizard gains 12 gold coins. Find the stakes of both owners.
Solution
Step 1: Let Variables
Let stake of first owner = \(x\)
Let stake of second owner = \(y\)
—Step 2: Form Equations
Case 1: First wins, second loses Wizard gets \(x\) and pays \( \frac{3}{4}y \)\[ x – \frac{3}{4}y = 12 \quad (1) \]
— Case 2: Second wins, first loses Wizard gets \(y\) and pays \( \frac{2}{3}x \)\[ y – \frac{2}{3}x = 12 \quad (2) \]
—Step 3: Remove Fractions
Multiply (1) by 4:\[ 4x – 3y = 48 \quad (3) \]
Multiply (2) by 3:\[ 3y – 2x = 36 \quad (4) \]
—Step 4: Solve Linear Equations
Add (3) and (4):\[ (4x – 3y) + (3y – 2x) = 48 + 36 \]
\[ 2x = 84 \Rightarrow x = 42 \]
Substitute into (4):\[ 3y – 2(42) = 36 \]
\[ 3y – 84 = 36 \]
\[ 3y = 120 \Rightarrow y = 40 \]
—Conclusion
\[ \text{First owner’s stake} = 42,\quad \text{Second owner’s stake} = 40 \]
Verification
Case 1: \(42 – 30 = 12\) ✔
Case 2: \(40 – 28 = 12\) ✔