Find x
Given:
\[ \begin{bmatrix} x & 2 \end{bmatrix} \begin{bmatrix} 3 \\ 4 \end{bmatrix} = 2 \]
Step 1: Multiply
\[ 3x + 2 \cdot 4 = 2 \]
\[ 3x + 8 = 2 \]
Step 2: Solve
\[ 3x = -6 \Rightarrow x = -2 \]
Final Answer:
\[ x = -2 \]
\[ \begin{bmatrix} x & 2 \end{bmatrix} \begin{bmatrix} 3 \\ 4 \end{bmatrix} = 2 \]
\[ 3x + 2 \cdot 4 = 2 \]
\[ 3x + 8 = 2 \]
\[ 3x = -6 \Rightarrow x = -2 \]
\[ x = -2 \]