Prove: \((a^{-1}+b^{-1})^{-1} = \frac{ab}{a+b}\)
Proof
\[ (a^{-1}+b^{-1})^{-1} \]
\[ = \left(\frac{1}{a} + \frac{1}{b}\right)^{-1} \]
\[ = \left(\frac{a+b}{ab}\right)^{-1} \]
\[ = \frac{ab}{a+b} \]
\[ (a^{-1}+b^{-1})^{-1} \]
\[ = \left(\frac{1}{a} + \frac{1}{b}\right)^{-1} \]
\[ = \left(\frac{a+b}{ab}\right)^{-1} \]
\[ = \frac{ab}{a+b} \]