If 49a² – b = (7a + 1/2)(7a – 1/2), then the value of b is

Question:

\[ 49a^2-b=(7a+\frac{1}{2})(7a-\frac{1}{2}) \]

(a) 0

(b) \(\frac{1}{4}\)

(c) \(\frac{1}{\sqrt{2}}\)

(d) \(\frac{1}{2}\)

Solution:

\[ (7a+\frac{1}{2})(7a-\frac{1}{2}) \]

\[ =(7a)^2-(\frac{1}{2})^2 \]

\[ =49a^2-\frac{1}{4} \]

\[ 49a^2-b=49a^2-\frac{1}{4} \]

\[ b=\frac{1}{4} \]

\[ \boxed{\frac{1}{4}} \]

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