Factorization of x² + y² − z² − 2xy
The polynomial \[ x^2+y^2-z^2-2xy \] on factorization gives _____________
Solution
\[ x^2+y^2-z^2-2xy \]
\[ =(x-y)^2-z^2 \]
\[ =[(x-y)-z][(x-y)+z] \]
\[ =(x-y-z)(x-y+z) \]
\[ \boxed{(x-y-z)(x-y+z)} \]
The polynomial \[ x^2+y^2-z^2-2xy \] on factorization gives _____________
\[ x^2+y^2-z^2-2xy \]
\[ =(x-y)^2-z^2 \]
\[ =[(x-y)-z][(x-y)+z] \]
\[ =(x-y-z)(x-y+z) \]
\[ \boxed{(x-y-z)(x-y+z)} \]