Value of {(2.3)³ − 0.027}/{(2.3)² + 0.69 + 0.09}
The value of \[ \frac{(2.3)^3-0.027}{(2.3)^2+0.69+0.09} \] is
(a) \(2\)
(b) \(3\)
(c) \(2.327\)
(d) \(2.273\)
Solution
\[ \frac{(2.3)^3-(0.3)^3}{(2.3)^2+(2.3)(0.3)+(0.3)^2} \]
Using identity:
\[ \frac{a^3-b^3}{a^2+ab+b^2}=a-b \]
\[ =2.3-0.3 \]
\[ =2 \]
Therefore,
\[ \boxed{(a)\ 2} \]