Let A = {a, b, {c, d}, e} | False Statements in Sets

Let A = {a, b, {c, d}, e}

Let \[ A=\{a,b,\{c,d\},e\} \] Which of the following statements are false and why?

(i) \(\{c,d\} \subset A\)

(ii) \(\{c,d\} \in A\)

(iii) \(\{\{c,d\}\} \subset A\)

(iv) \(a \in A\)

(v) \(a \subset A\)

(vi) \(\{a,b,e\} \subset A\)

(vii) \(\{a,b,e\} \in A\)

(viii) \(\{a,b,c\} \subset A\)

(ix) \(\Phi \in A\)

(x) \(\{0\} \subset A\)

Solution

Elements of \[ A \] are \[ a,\ b,\ \{c,d\},\ e \]

(i) False, because \[ c,d \notin A \]

(ii) True, because \[ \{c,d\} \in A \]

(iii) True, because \[ \{c,d\} \in A \]

(iv) True, because \[ a \in A \]

(v) False, because \[ a \] is not a set.

(vi) True, because all elements \[ a,b,e \] belong to \[ A \]

(vii) False, because \[ \{a,b,e\} \notin A \]

(viii) False, because \[ c \notin A \]

(ix) False, because \[ \Phi \notin A \]

(x) False, because \[ 0 \notin A \]

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