Find f+g, f-g, cf, fg, 1/f and f/g | Functions Class 11 Maths

Find f+g, f-g, cf (c ∈ R, c ≠ 0), fg, 1/f and f/g in each of the following.

(i) \(f(x)=x^3+1\) and \(g(x)=x+1\)

1. Find \(f+g\)

\[ (f+g)(x)=f(x)+g(x) \]
\[ =(x^3+1)+(x+1) \]
\[ =x^3+x+2 \]

2. Find \(f-g\)

\[ (f-g)(x)=f(x)-g(x) \]
\[ =(x^3+1)-(x+1) \]
\[ =x^3-x \]

3. Find \(cf\)

\[ (cf)(x)=c\cdot f(x) \]
\[ =c(x^3+1) \]
\[ =cx^3+c \]

4. Find \(fg\)

\[ (fg)(x)=f(x)\cdot g(x) \]
\[ =(x^3+1)(x+1) \]
\[ =x^4+x^3+x+1 \]

5. Find \(1/f\)

\[ \left(\frac{1}{f}\right)(x)=\frac{1}{x^3+1} \]

For reciprocal function, denominator should not be zero.

\[ x^3+1\neq 0 \]
\[ x\neq -1 \]

6. Find \(f/g\)

\[ \left(\frac{f}{g}\right)(x)=\frac{x^3+1}{x+1} \]
\[ =\frac{(x+1)(x^2-x+1)}{x+1} \]
\[ =x^2-x+1 \]

But denominator cannot be zero.

\[ x+1\neq 0 \]
\[ x\neq -1 \]

(ii) \(f(x)=\sqrt{x-1}\) and \(g(x)=\sqrt{x+1}\)

1. Find \(f+g\)

\[ (f+g)(x)=\sqrt{x-1}+\sqrt{x+1} \]

Domain:

\[ x-1\geq0 \]
\[ x+1\geq0 \]
\[ x\geq1 \]

2. Find \(f-g\)

\[ (f-g)(x)=\sqrt{x-1}-\sqrt{x+1} \]

Domain:

\[ x\geq1 \]

3. Find \(cf\)

\[ (cf)(x)=c\sqrt{x-1} \]

Domain:

\[ x\geq1 \]

4. Find \(fg\)

\[ (fg)(x)=\sqrt{x-1}\cdot\sqrt{x+1} \]
\[ =\sqrt{(x-1)(x+1)} \]
\[ =\sqrt{x^2-1} \]

Domain:

\[ x\geq1 \]

5. Find \(1/f\)

\[ \left(\frac{1}{f}\right)(x)=\frac{1}{\sqrt{x-1}} \]

Denominator should not be zero.

\[ x-1>0 \]
\[ x>1 \]

6. Find \(f/g\)

\[ \left(\frac{f}{g}\right)(x)=\frac{\sqrt{x-1}}{\sqrt{x+1}} \]

For domain:

\[ x-1\geq0 \]
\[ x+1>0 \]
\[ x\geq1 \]

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