Find the Value of k for Which the Roots Are Real and Equal
Solution
Given: $$2kx^2-40x+25=0$$
Here, $$a=2k,\quad b=-40,\quad c=25$$
For real and equal roots, $$D=b^2-4ac=0$$
$$(-40)^2-4(2k)(25)=0$$
$$1600-200k=0$$
$$200k=1600$$
$$k=8$$
Answer
The value of k for which the roots are real and equal is: $$\boxed{k=8}$$