Check Function \(f(x)=1+x^2\) on \( \mathbb{R} \)
📺 Video Explanation
📝 Question
Check whether the function
\[ f:\mathbb{R}\to\mathbb{R},\quad f(x)=1+x^2 \]
is:
- injection (one-one)
- surjection (onto)
- bijection
✅ Solution
🔹 Step 1: Check Injection (One-One)
Take:
\[ x=2,\quad x=-2 \]
Then:
\[ f(2)=1+4=5,\quad f(-2)=1+4=5 \]
But:
\[ 2\neq-2 \]
❌ Not one-one.
🔹 Step 2: Check Surjection (Onto)
Since:
\[ x^2\geq0 \]
Therefore:
\[ 1+x^2\geq1 \]
So range is:
\[ [1,\infty) \]
But codomain is:
\[ \mathbb{R} \]
Numbers like:
\[ 0,\ -2 \]
are not in range.
❌ Not onto.
🎯 Final Answer
\[ \boxed{\text{f is neither one-one nor onto}} \]
So:
❌ Injection
❌ Surjection
❌ Bijection
🚀 Exam Shortcut
- Square terms repeat values → not injective
- Addition shifts range upward
- Compare range with codomain carefully