RD Sharma Chapter 3: Pairs of Linear Equations in Two Variables Exercise 3.9 Solutions
A father is three times as old as his son. After twelve years, his age will be twice as that of his son then. Find their present ages. Watch Solution
Ten years later, A will be twice as old as B and five years ago, A was three times as old as B. What are the present ages of A and B ? Watch Solution
Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu. How old are Nuri and Sonu? Watch Solution
Six years hence a man’s age will be three times the age of his son and three years ago he was nine times as old as his son. Find their present ages. Watch Solution
Ten years ago, a father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be then. Find their present ages. Watch Solution
The present age of a father is three years more than three times the age of the son. Three years hence father’s age will be 10 years more than twice the age of the son. Determine their present ages. Watch Solution
A father is three times as old as his son. In 12 years time, he will be twice as old as hi son. Find the present ages of father and the son. Watch Solution
Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father. Watch Solution
Two years ago, a father was five times as old as his son. Two years later, his age will be 8 more than three times the age of the son. Find the present ages of father and son. Watch Solution
A is elder to B by 2 years. A’s father F is twice as old as A and B is twice as old as his sister S. If the ages of the father and sister differ by 40 years, find the age of A. Watch Solution
The ages of two friends Ani and Biju differ by 3 years. Ani’s father Dharam is twice as old as Ani and Biju as twice as old as his sister Cathy. The ages of Cathy and Dharam differ by 30 years. Find the ages of Ani and Biju. Watch Solution
Two years ago, Salim was thrice as old as his daughter and six years later, he will be four years older than twice her age. How old are they now? Watch Solution
The age of the father is twice the sum of the ages of his two children. After 20 years, his age will be equal to the sum of the ages of his children. Find the age of the father. Watch Solution
Pair of Linear Equations in Two Variables – R.D. Sharma Class 10th Math
