Class 11th Maths – RD Sharma Chapter 1 : Sets Exercise 1.6 Solutions
- Find the smallest set A such that A ∪ {1, 2} = {1, 2, 3, 5, 9}. Watch Solution
- Let A={1,2,4,5}, B={2,3,5,6}, C={4,5,6,7} Verify the following identity : A∩(B∪C) = (A ∩B)∪(A∩C) Watch Solution
- Let A={1,2,4,5}, B={2,3,5,6}, C={4,5,6,7} Verify the following identity : A∪(B∩C) = (A∪B)∩(A∪C) Watch Solution
- Let A={1,2,4,5}, B={2,3,5,6}, C={4,5,6,7} Verify the following identity : A∩(B – C) = (A∩B) – (A∩C) Watch Solution
- Let A={1,2,4,5}, B={2,3,5,6}, C={4,5,6,7} Verify the following identity : A – (B∪C) = (A – B)∩(A – C) Watch Solution
- Let A={1,2,4,5}, B={2,3,5,6}, C={4,5,6,7} Verify the following identity : A – (B∩C) = (A – B)∪(A – C) Watch Solution
- Let A={1,2,4,5}, B={2,3,5,6}, C={4,5,6,7} Verify the following identity : A∩(B Δ C) = (A∩B) Δ (A∩C) Watch Solution
- If U = {2,3,5,7,9} is the universal set A = {3,7}, B = {2,5,7,9} then prove that : (A∪B)’ = A’ ∩ B’ Watch Solution
- If U = {2,3,5,7,9} is the universal set A = {3,7}, B = {2,5,7,9} then prove that : (A∩B)’ = A’ ∪ B’ Watch Solution
- For any two set A and B , prove that B ⊂ A ∪ B Watch Solution
- For any two sets A and B, prove that : B ⊂ A ∪ B Watch Solution
- For any two sets A and B, prove that : A ∩ B ⊂ A Watch Solution
- For any two sets A and B, prove that : A ⊂ B ⟹ A ∩ B = A. Watch Solution
- For any two sets A and B, show that the following statements are equivalent : (i) A ⊂ B (ii) A – B = Φ (iii) A ∪ B = B (iv) A ∩ B = A Watch Solution
- For three sets A, B and C, show that A ⋂ B = A ⋂ C need not imply B = C. Watch Solution
- For three sets A, B and C, show that A ⊂ B ⇒ C – B ⊂ C – A Watch Solution
- For any tow sets, prove that : A ⋃ (A ⋂ B) = A Watch Solution
- For any two sets, prove that : A ⋂ (A ⋃ B) = A Watch Solution
- Find sets A, B and C such that A ⋂ B, A ⋂ C and B ⋂ C are non-empty sets and A⋂B⋂C = Φ Watch Solution
- For any two sets A and B, prove that: A⋂B = Φ ⟺ A ⊆ B’. Watch Solution
- If A and B are sets, then prove that A – B, A⋂B and B – A are pair wise disjoint. Watch Solution
- Using properties of sets, show that for any two sets A and B, (A⋃B) ⋂ (A⋃B’) = A Watch Solution
- For any two sets of A and B, prove that: A’⋃B = U ⇒ A ⊂ B Watch Solution
- For any two sets of A and B, prove that: B’ ⊂ A’ ⇒ A ⊂ B Watch Solution
- Is it true that for any sets A and B, P(A) ⋃ P(B) = P(A⋃B) ? Justify your answer. Watch Solution
- Show that for any sets A and B, A = (A ⋂ B) ⋃ (A – B) Watch Solution
- Show that for any sets A and B, A ⋃ (B – A) = A ⋃ B Watch Solution
- Each set X, contains 5 elements and each set Y, contains 2 elements and 20Ur=1 Xr=S=nUr=1Yr. If each element of S belongs to exactly 10 of the Xr’^s and the exactly 4 of Yr’^s, then find the value of n. Watch Solution
Chapter 1: Sets – R. D. Sharma Class 11th Maths
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Sets Exercise 1.1 Video Solution
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Sets Exercise 1.2 Video Solution
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Sets Exercise 1.3 Video Solution
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Sets Exercise 1.4 Video Solution
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Sets Exercise 1.5 Video Solution
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Sets Exercise 1.6 Video Solution
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Sets Exercise 1.7 Video Solution
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Sets Exercise 1.8 Video Solution
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Sets Multiple Choice Questions (MCQs) Video Solution Video Solution
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Sets Fill in the Blanks (FBQs) Video Solution
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Sets Very Short Answer Questions (VSAQs) Video Solution Video Solution