Evaluate \( \tan\left(\frac{1}{2}\sin^{-1}\left(\frac{3}{4}\right)\right) \)
Solution:
Let
\[ \theta = \sin^{-1}\left(\frac{3}{4}\right) \]
Then,
\[ \sin \theta = \frac{3}{4} \]
Consider a right triangle:
- Opposite = 3
- Hypotenuse = 4
So,
\[ \cos \theta = \sqrt{1 – \sin^2\theta} = \frac{\sqrt{7}}{4} \]
Using half-angle identity:
\[ \tan\left(\frac{\theta}{2}\right) = \frac{1 – \cos\theta}{\sin\theta} \]
\[ = \frac{1 – \frac{\sqrt{7}}{4}}{\frac{3}{4}} \]
\[ = \frac{\frac{4 – \sqrt{7}}{4}}{\frac{3}{4}} \]
\[ = \frac{4 – \sqrt{7}}{3} \]
Final Answer:
\[ \tan\left(\frac{1}{2}\sin^{-1}\left(\frac{3}{4}\right)\right) = \frac{4 – \sqrt{7}}{3} \]