Principal Value of sec⁻¹(√2) + 2cosec⁻¹(−√2)

Evaluate: sec-1(√2) + 2cosec-1(−√2)

Solution:

Step 1: Evaluate sec⁻¹(√2)

\[ \sec^{-1}(\sqrt{2}) \Rightarrow \cos y = \frac{1}{\sqrt{2}} \]

\[ y = \frac{\pi}{4} \]

(Principal range: \([0,\pi], y \ne \pi/2\))

Step 2: Evaluate cosec⁻¹(−√2)

\[ \csc^{-1}(-\sqrt{2}) \Rightarrow \sin y = -\frac{1}{\sqrt{2}} \]

\[ y = -\frac{\pi}{4} \]

(Principal range: \([-\pi/2,0) \cup (0,\pi/2]\))

Step 3: Substitute

\[ \frac{\pi}{4} + 2\left(-\frac{\pi}{4}\right) \]

\[ = \frac{\pi}{4} – \frac{\pi}{2} = -\frac{\pi}{4} \]

Final Answer:

Value = \[ -\frac{\pi}{4} \]

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