Find Symmetric Matrix B
Given:
\[ A = \begin{bmatrix} 1 & 2 \\ 0 & 3 \end{bmatrix} \]
Formula:
\[ B = \frac{1}{2}(A + A^T) \]
Step 1: Find AT
\[ A^T = \begin{bmatrix} 1 & 0 \\ 2 & 3 \end{bmatrix} \]
Step 2: Compute A + AT
\[ A + A^T = \begin{bmatrix} 1 & 2 \\ 0 & 3 \end{bmatrix} + \begin{bmatrix} 1 & 0 \\ 2 & 3 \end{bmatrix} = \begin{bmatrix} 2 & 2 \\ 2 & 6 \end{bmatrix} \]
Step 3: Multiply by 1/2
\[ B = \frac{1}{2} \begin{bmatrix} 2 & 2 \\ 2 & 6 \end{bmatrix} = \begin{bmatrix} 1 & 1 \\ 1 & 3 \end{bmatrix} \]
Final Answer:
\[ \boxed{ B = \begin{bmatrix} 1 & 1 \\ 1 & 3 \end{bmatrix} } \]