Binary Operation on Rational Set

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Determine whether the operation is a binary operation or not

Given:

\( S = \left\{ \frac{m}{n} : m \in \mathbb{Z}, \; n = 1,2,3 \right\} \)

Operation:

\( a * b = ab \)

Concept:

A binary operation must satisfy closure.

Solution:

Take two elements from the set:

\( a = \frac{1}{2}, \quad b = \frac{1}{3} \)

Then:

\( a * b = \frac{1}{2} \times \frac{1}{3} = \frac{1}{6} \)

But denominator 6 is not allowed (only 1, 2, 3 are allowed).

\( \frac{1}{6} \notin S \)

Conclusion:

The set is not closed under multiplication.

❌ Therefore, the operation is NOT a binary operation on \( S \).

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