Inverse of 4 under a*b = a + b + 2

Question:

On the set \( \mathbb{Z} \) of all integers, a binary operation \( * \) is defined by:

\[ a * b = a + b + 2 \]

Find the inverse of 4.

Solution:

Step 1: Find Identity Element

Let identity be \( e \), then:

\[ a * e = a \]

\[ a + e + 2 = a \]

\[ e + 2 = 0 \Rightarrow e = -2 \]

Step 2: Find inverse of 4

Let inverse of 4 be \( x \), then:

\[ 4 * x = e = -2 \]

\[ 4 + x + 2 = -2 \]

\[ x + 6 = -2 \]

\[ x = -8 \]

Step 3: Verify

\[ 4 * (-8) = 4 – 8 + 2 = -2 \]

Which equals identity, so correct.

Final Answer:

\[ \boxed{-8} \]

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