Sketch the Graph of Φ(x) = 2 cos(x − π/6)

Question:

Sketch the graph of the following trigonometric function :

\[ \Phi(x)=2\cos\left(x-\frac{\pi}{6}\right) \]

Solution:

We know that

\[ y=\cos x \]

is the standard cosine curve.

The graph of

\[ y=2\cos\left(x-\frac{\pi}{6}\right) \]

is obtained by:

  • Stretching the cosine curve vertically by factor \(2\)
  • Shifting it to the right by \(\dfrac{\pi}{6}\)

Important properties:

  • Amplitude \(=2\)
  • Period \(=2\pi\)
  • Phase shift \(=\dfrac{\pi}{6}\) to the right
  • Range \(-2 \le y \le 2\)

Now calculate some important points:

\[ \begin{aligned} x=0 &\Rightarrow y=2\cos\left(-\frac{\pi}{6}\right) =\sqrt3\\[8pt] x=\frac{\pi}{6} &\Rightarrow y=2\cos0=2\\[8pt] x=\frac{2\pi}{3} &\Rightarrow y=2\cos\frac{\pi}{2}=0\\[8pt] x=\frac{7\pi}{6} &\Rightarrow y=2\cos\pi=-2\\[8pt] x=\frac{5\pi}{3} &\Rightarrow y=2\cos\frac{3\pi}{2}=0\\[8pt] x=\frac{13\pi}{6} &\Rightarrow y=2\cos2\pi=2 \end{aligned} \]

Thus the curve passes through the points

\[ (0,\sqrt3),\quad \left(\frac{\pi}{6},2\right),\quad \left(\frac{2\pi}{3},0\right),\quad \left(\frac{7\pi}{6},-2\right),\quad \left(\frac{5\pi}{3},0\right) \]

Plot these points and draw a smooth cosine curve through them.

π/6 2π/3 7π/6 5π/3 13π/6 2 √3 -2

Hence, the required graph is shown above.

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