Check One-One / Onto
🎥 Video Explanation
📝 Question
Let \( f:\mathbb{R} \to \mathbb{R} \) be defined by
\[ f(x)=(x-1)(x-2)(x-3) \]
- A. one-one but not onto
- B. onto but not one-one
- C. both one-one and onto
- D. neither one-one nor onto
✅ Solution
🔹 Step 1: Nature of Function
\(f(x)\) is a cubic polynomial.
As \(x \to \infty\), \(f(x) \to \infty\)
As \(x \to -\infty\), \(f(x) \to -\infty\)
✔️ Covers all real values ⇒ Onto
—🔹 Step 2: Check Injective
Cubic with turning points ⇒ not strictly monotonic.
Example:
\[ f(1)=0,\quad f(2)=0,\quad f(3)=0 \]
Different inputs → same output ⇒ ❌ Not one-one
—🔹 Final Answer
\[ \boxed{\text{Option B: onto but not one-one}} \]