Check Which Functions are Bijective
🎥 Video Explanation
📝 Question
Let \(A=\{x\in\mathbb{R}:-1\le x\le 1\}\).
Which of the following functions \(A \to A\) are bijections?
- A. \(f(x)=|x|\)
- B. \(f(x)=\sin\left(\frac{\pi x}{2}\right)\)
- C. \(f(x)=\sin\left(\frac{\pi x}{4}\right)\)
- D. none of these
✅ Solution
🔹 Option A: \(f(x)=|x|\)
\[ f(-x)=f(x) \]
❌ Not one-one ⇒ Not bijective
—🔹 Option B: \(f(x)=\sin\left(\frac{\pi x}{2}\right)\)
Strictly increasing on \([-1,1]\)
\[ f(-1)=-1,\quad f(1)=1 \]
Range: \[ [-1,1] \]
✔️ One-one and onto ⇒ Bijective
—🔹 Option C: \(f(x)=\sin\left(\frac{\pi x}{4}\right)\)
Range:
\[ \left[-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right] \]
Not equal to \([-1,1]\)
❌ Not onto ⇒ Not bijective
—🔹 Final Answer
\[ \boxed{\text{Option B}} \]