Value of sec⁻¹(1/2)

Question

Find the value of:

\[ \sec^{-1}\left(\frac{1}{2}\right) \]

Solution

We know:

\[ \sec^{-1}(x) = \cos^{-1}\left(\frac{1}{x}\right) \]

So,

\[ \sec^{-1}\left(\frac{1}{2}\right) = \cos^{-1}(2) \]

But cosine function satisfies:

\[ -1 \le \cos \theta \le 1 \]

Since \( 2 \) is outside this range,

\[ \cos^{-1}(2) \text{ is not defined in real numbers} \]

Final Answer:

\[ \boxed{\text{Not defined (no real value)}} \]

Key Concept

The domain of \( \sec^{-1}x \) is \( |x| \ge 1 \). Since \( \frac{1}{2} \in (-1,1) \), it has no real value.

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