Value of sin(2 tan⁻¹(0.75))

Question

Evaluate:

\[ \sin\left(2\tan^{-1}(0.75)\right) \]

Solution

Let

\[ \theta = \tan^{-1}(0.75) = \tan^{-1}\left(\frac{3}{4}\right) \]

Then,

\[ \tan\theta = \frac{3}{4} \Rightarrow \text{Opposite} = 3,\ \text{Adjacent} = 4 \Rightarrow \text{Hypotenuse} = 5 \]

\[ \sin\theta = \frac{3}{5}, \quad \cos\theta = \frac{4}{5} \]

Now use identity:

\[ \sin 2\theta = 2\sin\theta \cos\theta \]

\[ = 2 \cdot \frac{3}{5} \cdot \frac{4}{5} = \frac{24}{25} \]

Final Answer:

\[ \boxed{\frac{24}{25}} \]

Key Concept

Convert into triangle form and apply double-angle identity.

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