Question
\[ \text{If } \sin x=-\frac{24}{25}, \]
\[ \text{then the value of } \tan x \text{ is} \]
Solution
Using identity
\[ \sin^2x+\cos^2x=1 \]
\[ \left(-\frac{24}{25}\right)^2+\cos^2x=1 \]
\[ \frac{576}{625}+\cos^2x=1 \]
\[ \cos^2x=\frac{49}{625} \]
\[ \cos x=\pm\frac{7}{25} \]
Now,
\[ \tan x=\frac{\sin x}{\cos x} \]
\[ =\frac{-24/25}{\pm7/25} \]
\[ \tan x=\pm\frac{24}{7} \]
Since quadrant is not given, both signs are possible.
Answer
\[ \boxed{\pm\frac{24}{7}} \]