Solve the Following Quadratic Equation by Factorization

Question:

\[ x^2+\left(a+\frac1a\right)x+1=0 \]

Solution

Given,

\[ x^2+\left(a+\frac1a\right)x+1=0 \]

Splitting the middle term:

\[ x^2+ax+\frac{x}{a}+1=0 \]

Taking common factors:

\[ x(x+a)+\frac1a(x+a)=0 \] \[ (x+a)\left(x+\frac1a\right)=0 \]

Therefore,

\[ x+a=0 \] or \[ x+\frac1a=0 \] \[ x=-a \] or \[ x=-\frac1a \]

Final Answer

\[ \boxed{x=-a \quad \text{or} \quad x=-\frac1a} \]

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