Find the Values of k for Which the Equation Has Equal Roots
Solution
Given: $$4x^2+kx+3=0$$
Here, $$a=4,\quad b=k,\quad c=3$$
For equal roots, $$D=b^2-4ac=0$$
$$k^2-4(4)(3)=0$$
$$k^2-48=0$$
$$k=\pm\sqrt{48}=\pm4\sqrt3$$
Answer
The value(s) of k for which the roots are equal is: $$\boxed{k=\pm4\sqrt3}$$