Binary Operation on Natural Numbers

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Determine whether the operation is a binary operation or not

Given: An operation \( O \) on \( \mathbb{N} \) defined by

\( a \, O \, b = a^b + b^a \quad \forall \, a, b \in \mathbb{N} \)

Concept:

A binary operation on a set must satisfy the closure property, meaning the result must always belong to the same set.

Solution:

Let \( a, b \in \mathbb{N} \).

\( a \, O \, b = a^b + b^a \)

Since:

  • \( a^b \in \mathbb{N} \)
  • \( b^a \in \mathbb{N} \)

The sum of two natural numbers is also a natural number.

\( a^b + b^a \in \mathbb{N} \)

Conclusion:

The result always belongs to \( \mathbb{N} \), so the set is closed under this operation.

✔ Therefore, the operation is a binary operation on \( \mathbb{N} \).

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