Question:
Factorize: \[ x(x-2)(x-4)+4x-8 \]
Solution:
\[ x(x-2)(x-4)+4x-8 \]
\[ =x(x-2)(x-4)+4(x-2) \]
\[ =(x-2)\{x(x-4)+4\} \]
\[ =(x-2)(x^2-4x+4) \]
\[ =(x-2)(x-2)^2 \]
\[ =(x-2)^3 \]
\[ \boxed{(x-2)^3} \]
Factorize: \[ x(x-2)(x-4)+4x-8 \]
\[ x(x-2)(x-4)+4x-8 \]
\[ =x(x-2)(x-4)+4(x-2) \]
\[ =(x-2)\{x(x-4)+4\} \]
\[ =(x-2)(x^2-4x+4) \]
\[ =(x-2)(x-2)^2 \]
\[ =(x-2)^3 \]
\[ \boxed{(x-2)^3} \]