Find the Value of k for Which the Roots Are Real and Equal
Solution
Given: $$kx^2+4x+1=0$$
Here, $$a=k,\quad b=4,\quad c=1$$
For real and equal roots, $$D=b^2-4ac=0$$
$$4^2-4(k)(1)=0$$
$$16-4k=0$$
$$k=4$$
Answer
The value of k for which the roots are real and equal is: $$\boxed{k=4}$$