Question

Find the values of the following trigonometric ratios :

\[ \sin 17\pi \]

Solution

\[ \sin 17\pi = \sin(n\pi) \]

Using,

\[ \sin(n\pi)=0 \]

Therefore,

\[ \sin 17\pi = 0 \]

Answer :

\[ \boxed{ \sin 17\pi = 0 } \]