Prove That A’∪B = U ⇒ A ⊂ B

Prove That A’∪B = U ⇒ A ⊂ B

Question:

For any two sets \( A \) and \( B \), prove that:

\[ A’\cup B=U \Rightarrow A\subset B \]

Solution

\[ A’\cup B=U \]

Taking complement on both sides,

\[ (A’\cup B)’=U’ \] \[ A”\cap B’=\phi \] \[ A\cap B’=\phi \] \[ A\subset B \]

Hence proved.

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