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Q. If \( g = t^{\frac{2}{3}} + 4t^{-\frac{1}{2}} \), find \( g \) when \( t = 64 \)
(a) \( \frac{31}{2} \) (b) \( \frac{33}{2} \) (c) 16 (d) \( \frac{257}{16} \)
✏️ Solution
\( g = 64^{2/3} + 4 \cdot 64^{-1/2} \)
\( = 16 + 4 \cdot \frac{1}{8} \)
\( = 16 + \frac{1}{2} \)
\( = \frac{33}{2} \)
Correct Option: (b) \( \frac{33}{2} \)
\( \boxed{\frac{33}{2}} \)