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Q. If \( x^{-2} = 64 \), find \( x^{\frac{1}{3}} + x^0 \)
(a) 2 (b) 3 (c) \( \frac{3}{2} \) (d) \( \frac{2}{3} \)
тЬПя╕П Solution
\( x^{-2} = 64 \)
\( \frac{1}{x^2} = 64 \)
\( x^2 = \frac{1}{64} \)
\( x = \frac{1}{8} \)
\( x^{1/3} = \left(\frac{1}{8}\right)^{1/3} \)
\( = \frac{1}{2} \)
\( x^0 = 1 \)
\( x^{1/3} + x^0 = \frac{1}{2} + 1 \)
\( = \frac{3}{2} \)
Correct Option: (c) \( \frac{3}{2} \)
\( \boxed{\frac{3}{2}} \)