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Q. If \( x = 8^{\frac{2}{3}} \times 32^{-\frac{2}{5}} \), find \( x^{-5} \)
✏️ Solution
\( x = (2^3)^{\frac{2}{3}} \times (2^5)^{-\frac{2}{5}} \)
\( = 2^{2} \times 2^{-2} \)
\( = 2^{2-2} \)
\( = 2^0 \)
\( = 1 \)
\( \therefore x^{-5} = 1^{-5} \)
\( = 1 \)
Final Answer: \( \boxed{1} \)