If x/cos θ = y/cos(θ − 2π/3) = z/cos(θ + 2π/3), Find x + y + z
If \[ \frac{x}{\cos\theta} = \frac{y}{\cos\left(\theta-\frac{2\pi}{3}\right)} = \frac{z}{\cos\left(\theta+\frac{2\pi}{3}\right)} \] then \[ x+y+z \] = ……………………………………
Solution
Let
\[ \frac{x}{\cos\theta} = \frac{y}{\cos\left(\theta-\frac{2\pi}{3}\right)} = \frac{z}{\cos\left(\theta+\frac{2\pi}{3}\right)} =k \]
Then,
\[ x=k\cos\theta \]
\[ y=k\cos\left(\theta-\frac{2\pi}{3}\right) \]
\[ z=k\cos\left(\theta+\frac{2\pi}{3}\right) \]
Therefore,
\[ x+y+z = k\left[ \cos\theta + \cos\left(\theta-\frac{2\pi}{3}\right) + \cos\left(\theta+\frac{2\pi}{3}\right) \right] \]
Using the identities:
\[ \cos\left(\theta-\frac{2\pi}{3}\right) = -\frac{1}{2}\cos\theta+\frac{\sqrt3}{2}\sin\theta \]
and
\[ \cos\left(\theta+\frac{2\pi}{3}\right) = -\frac{1}{2}\cos\theta-\frac{\sqrt3}{2}\sin\theta \]
Adding all three terms,
\[ \cos\theta -\frac{1}{2}\cos\theta -\frac{1}{2}\cos\theta + \frac{\sqrt3}{2}\sin\theta -\frac{\sqrt3}{2}\sin\theta =0 \]
Hence,
\[ x+y+z=0 \]
Therefore,
\[ \boxed{0} \]