Prove: \[ \frac{(0.6)^0 – (0.1)^{-1}}{(3/8)^{-1}(3/2)^3 – (1/3)^{-1}} = -\frac{3}{2} \]
Solution
\[ = \frac{1 – 10}{\frac{8}{3}\cdot \frac{27}{8} – 3} \]
\[ = \frac{-9}{9 – 3} \]
\[ = \frac{-9}{6} \]
\[ = -\frac{3}{2} \]
\[ = \frac{1 – 10}{\frac{8}{3}\cdot \frac{27}{8} – 3} \]
\[ = \frac{-9}{9 – 3} \]
\[ = \frac{-9}{6} \]
\[ = -\frac{3}{2} \]