Prove: \[ 9^{3/2} – 3\times 5^0 – (1/81)^{-1/2} = 15 \]
Solution
\[ 9^{3/2} = (3^2)^{3/2} = 3^3 = 27 \]
\[ 5^0 = 1 \]
\[ (1/81)^{-1/2} = (3^{-4})^{-1/2} = 3^2 = 9 \]
\[ = 27 – 3\times 1 – 9 \]
\[ = 27 – 3 – 9 \]
\[ = 15 \]
\[ 9^{3/2} = (3^2)^{3/2} = 3^3 = 27 \]
\[ 5^0 = 1 \]
\[ (1/81)^{-1/2} = (3^{-4})^{-1/2} = 3^2 = 9 \]
\[ = 27 – 3\times 1 – 9 \]
\[ = 27 – 3 – 9 \]
\[ = 15 \]