Solve the Following Quadratic Equation by Factorization

Question:

\[ 7x+\frac{3}{x}=35\frac{3}{5} \]

Solution

Convert the mixed fraction into an improper fraction:

\[ 35\frac{3}{5}=\frac{178}{5} \]

Therefore,

\[ 7x+\frac{3}{x}=\frac{178}{5} \]

Multiplying both sides by \(5x\):

\[ 35x^2+15=178x \] \[ 35x^2-178x+15=0 \]

Factorizing:

\[ 35x^2-175x-3x+15=0 \] \[ 35x(x-5)-3(x-5)=0 \] \[ (x-5)(35x-3)=0 \]

Therefore,

\[ x-5=0 \] or \[ 35x-3=0 \] \[ x=5 \] or \[ x=\frac{3}{35} \]

Final Answer

\[ \boxed{x=5 \quad \text{or} \quad x=\frac{3}{35}} \]

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