Question:
\[ (x^2-1)(x^4+x^2+1) \] is equal to
(a) \(x^8-1\)
(b) \(x^8+1\)
(c) \(x^6-1\)
(d) \(x^6+1\)
Solution:
\[ =(x^2-1)(x^4+x^2+1) \]
\[ =(x^2)^3-1^3 \]
\[ =x^6-1 \]
\[ \boxed{x^6-1} \]
\[ (x^2-1)(x^4+x^2+1) \] is equal to
(a) \(x^8-1\)
(b) \(x^8+1\)
(c) \(x^6-1\)
(d) \(x^6+1\)
\[ =(x^2-1)(x^4+x^2+1) \]
\[ =(x^2)^3-1^3 \]
\[ =x^6-1 \]
\[ \boxed{x^6-1} \]