The value of sin(π/18) + sin(π/9) + sin(2π/9) + sin(5π/18)

The value of \( \sin\frac{\pi}{18}+\sin\frac{\pi}{9}+\sin\frac{2\pi}{9}+\sin\frac{5\pi}{18} \) is given by

Options:
(a) \( \sin\frac{7\pi}{18}+\sin\frac{4\pi}{9} \)
(b) \(1\)
(c) \( \cos\frac{\pi}{6}+\cos\frac{3\pi}{7} \)
(d) \( \cos\frac{\pi}{9}+\sin\frac{\pi}{9} \)
Solution:
\[ =\sin\frac{\pi}{18}+\sin\frac{5\pi}{18} + \sin\frac{\pi}{9}+\sin\frac{2\pi}{9} \]
Using identity, \[ \sin A+\sin B = 2\sin\frac{A+B}{2}\cos\frac{A-B}{2} \]
\[ = 2\sin\frac{6\pi}{36}\cos\frac{4\pi}{36} + 2\sin\frac{3\pi}{18}\cos\frac{\pi}{18} \]
\[ = 2\sin\frac{\pi}{6}\cos\frac{\pi}{9} + 2\sin\frac{\pi}{6}\cos\frac{\pi}{18} \]
Since, \[ 2\sin\frac{\pi}{6}=1 \]
\[ = \cos\frac{\pi}{9}+\cos\frac{\pi}{18} \]
Using, \[ \cos\frac{\pi}{18}=\sin\left(\frac{\pi}{2}-\frac{\pi}{18}\right) =\sin\frac{4\pi}{9} \]
\[ = \cos\frac{\pi}{9}+\sin\frac{4\pi}{9} \]
\[ = \sin\frac{7\pi}{18}+\sin\frac{4\pi}{9} \]
\[ \boxed{\sin\frac{7\pi}{18}+\sin\frac{4\pi}{9}} \]
Correct option: (a)

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