Question
\[
\left(\frac{1}{9}\right)^{-1/2} \times 64^{-1/3}
\]
Solution
\[
\left(\frac{1}{9}\right)^{-1/2} = 9^{1/2}
\]
\[
= 3
\]
\[
64^{-1/3} = \frac{1}{64^{1/3}}
\]
\[
= \frac{1}{4}
\]
\[
= 3 \times \frac{1}{4}
\]
\[
= \frac{3}{4}
\]
Answer
\[
\boxed{\frac{3}{4}}
\]