Class 10 Maths – RD Sharma Chapter 1: Real Numbers Exercise 1.4 Solution (Step-by-Step Guide)

Class 10 Maths – RD Sharma Chapter 1: Real Numbers Exercise 1.4 Solution (Step-by-Step Guide)

1. Find the LCM and HCF of the pairs of integers and verify that LCM × HCF = Product of the integers: 26 and 91 Watch Solution
2. Find the LCM and HCF of the pairs of integers and verify that LCM × HCF = Product of the integers: 510 and 92. Watch Solution
3. Find the LCM and HCF of the pairs of integers and verify that LCM × HCF = Product of the integers: 336 and 54. Watch Solution
4. Find the LCM and HCF of the pairs of integers and verify that LCM × HCF = Product of the integers: 404 and 96. Watch Solution
5. Find the LCM and HCF of the integers by applying the prime factorization method: 12, 15 and 21. Watch Solution
6. Find the LCM and HCF of the integers by applying the prime factorization method: 17,23 and 29. Watch Solution
7. Find the LCM and HCF of the integers by applying the prime factorization method: 8,9 and 25. Watch Solution
8. Find the LCM and HCF of the integers by applying the prime factorization method: 40,36 and 126. Watch Solution
9. Find the LCM and HCF of the integers by applying the prime factorization method: 84 , 90 and 120. Watch Solution
10. Find the LCM and HCF of the integers by applying the prime factorization method: 24,15 and 36. Watch Solution
11. Given that HCF (306, 657) = 9, find LCM ( 306, 657 ). Watch Solution
12. Write the smallest number which is divisible by both 306 and 657. Watch Solution
13. Can two numbers have 16 as their HCF and 380 as their LCM? Give reason. Watch Solution
14. The HCF of the two numbers is 145, and their LCM is 2175. If one number is 725, find the other. Watch Solution
15. The HCF of the two numbers is 16, and their product is 3072. Find their LCM. Watch Solution
16. The LCM and HCF of the two numbers are 180 and 6, respectively. If one of the numbers is 30, find the other number. Watch Solution
17. Find the smallest number that, when increased by 17, is exactly divisible by both 520 and 468. Watch Solution
18. Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32, respectively. Watch Solution
19. What is the smallest number that, when divided by 35, 56 and 91, leaves remainders of 7 in each case? Watch Solution
20. A rectangular courtyard is 18m 72cm long and 13m 20 cm broad. It is to be paved with square tiles of the same size. Find the least possible number of such tiles. Watch Solution
21. Find the greatest number of 6 digits exactly divisible by 24, 15 and 36. Watch Solution
22. Determine the number nearest to 110000 but greater than 100000, which is exactly divisible by each of 8, 15 and 21. Watch Solution
23. Find the least number that is divisible by all the numbers between 1 and 10 (both inclusive). Watch Solution
24. A circular field has a circumference of 360 km. Three cyclists start together and can cycle 48,60 and 72 km a day around the field. When will they meet again? Watch Solution
25. In a morning walk, three persons step off together, their steps measuring 80 cm, 85 cm and 90 cm, respectively. What is the minimum distance each should walk so that he can cover the distance in complete steps? Watch Solution
26. On a morning walk, three persons step out together and their steps measure 30 cm, 36 cm and 40 cm respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps? Watch Solution
27. Find the largest number which on dividing 1251, 9377 and 15628 leaves remainders 1, 2 and 3 respectively. Watch Solution

1. Real Numbers – R.D. Sharma Class 10th Math

1. Real Numbers Exercise 1.1 Video Solution

2. Real Numbers Exercise 1.2 Video Solution

3. Real Numbers Exercise 1.3 Video Solution

4. Real Numbers Exercise 1.4 Video Solution

5. Real Numbers Exercise 1.5 Video Solution

6. Real Numbers Exercise 1.6 Video Solution

7. Real Numbers Multiple Choice Questions (MCQs) Video Solution Video Solution

8. Real Numbers Fill in the Blanks (FBQs) Video Solution

9. Real Numbers Very Short Answer Questions (VSAQs) Video Solution Video Solution