Question

\[ \frac{\sin70^\circ}{\sin110^\circ} \]

Solution

Using identity

\[ \sin(180^\circ-\theta)=\sin\theta \]

\[ \sin110^\circ = \sin(180^\circ-70^\circ) \]

\[ =\sin70^\circ \]

Therefore,

\[ \frac{\sin70^\circ}{\sin110^\circ} = \frac{\sin70^\circ}{\sin70^\circ} =1 \]

Answer

\[ \boxed{1} \]