Solve the Following Quadratic Equation by Factorization

Question:

\[ a(x^2+1)-x(a^2+1)=0 \]

Solution

Given,

\[ a(x^2+1)-x(a^2+1)=0 \]

Expanding,

\[ ax^2+a-a^2x-x=0 \] \[ ax^2-(a^2+1)x+a=0 \]

Splitting the middle term:

\[ ax^2-a^2x-x+a=0 \]

Taking common factors:

\[ ax(x-a)-1(x-a)=0 \] \[ (x-a)(ax-1)=0 \]

Therefore,

\[ x-a=0 \] or \[ ax-1=0 \] \[ x=a \] or \[ x=\frac{1}{a} \]

Final Answer

\[ \boxed{x=a \quad \text{or} \quad x=\frac{1}{a}} \]

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