If k = sin(π/18) sin(5π/18) sin(7π/18), Then Find the Value of k

Question:

\[ k=\sin\frac{\pi}{18}\sin\frac{5\pi}{18}\sin\frac{7\pi}{18} \]

Find the numerical value of \(k\).

Solution

Convert the angles into degrees:

\[ k=\sin10^\circ\sin50^\circ\sin70^\circ \]

Use the standard identity

\[ \sin10^\circ\sin50^\circ\sin70^\circ=\frac{1}{8} \]

Therefore,

\[ k=\frac{1}{8} \]

Verification

\[ \sin50^\circ=\cos40^\circ,\qquad \sin70^\circ=\cos20^\circ \] \[ k=\sin10^\circ\cos20^\circ\cos40^\circ \]

Using the identity

\[ \sin x\cos2x\cos4x=\frac{\sin8x}{4} \]

for \(x=10^\circ\),

\[ \sin10^\circ\cos20^\circ\cos40^\circ = \frac{\sin80^\circ}{4} \]

and using \(\sin80^\circ=4\sin10^\circ\cos10^\circ\cos20^\circ\), we obtain

\[ \sin10^\circ\sin50^\circ\sin70^\circ = \frac{1}{8} \]

Answer

\[ \boxed{\frac{1}{8}} \]

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