Find n(B), n(A−B) and n(B−A)
Question:
Let \( A \) and \( B \) be two sets such that:
\[ n(A)=20,\quad n(A\cup B)=42,\quad n(A\cap B)=4 \]Find:
\[ (i)\ n(B) \] \[ (ii)\ n(A-B) \] \[ (iii)\ n(B-A) \]Solution
(i) Find \( n(B) \)
\[ n(A\cup B)=n(A)+n(B)-n(A\cap B) \] \[ 42=20+n(B)-4 \] \[ 42=16+n(B) \] \[ n(B)=26 \](ii) Find \( n(A-B) \)
\[ n(A-B)=n(A)-n(A\cap B) \] \[ =20-4 \] \[ =16 \](iii) Find \( n(B-A) \)
\[ n(B-A)=n(B)-n(A\cap B) \] \[ =26-4 \] \[ =22 \]Hence,
\[ \boxed{n(B)=26} \] \[ \boxed{n(A-B)=16} \] \[ \boxed{n(B-A)=22} \]