Solve: \(2^{x+1} = 4^{x-3}\)
Solution
\[ 2^{x+1} = (2^2)^{x-3} \]
\[ = 2^{x+1} = 2^{2x-6} \]
\[ \Rightarrow x + 1 = 2x – 6 \]
\[ \Rightarrow x = 7 \]
Final Answer:
\[ \boxed{x = 7} \]
\[ 2^{x+1} = (2^2)^{x-3} \]
\[ = 2^{x+1} = 2^{2x-6} \]
\[ \Rightarrow x + 1 = 2x – 6 \]
\[ \Rightarrow x = 7 \]
\[ \boxed{x = 7} \]