Solve: \(7^{2x+3} = 1\)
Solution
\[ 7^{2x+3} = 1 \]
\[ \text{Since } 7^0 = 1 \]
\[ \Rightarrow 2x + 3 = 0 \]
\[ \Rightarrow 2x = -3 \]
\[ \Rightarrow x = -\frac{3}{2} \]
Final Answer:
\[ \boxed{x = -\frac{3}{2}} \]
\[ 7^{2x+3} = 1 \]
\[ \text{Since } 7^0 = 1 \]
\[ \Rightarrow 2x + 3 = 0 \]
\[ \Rightarrow 2x = -3 \]
\[ \Rightarrow x = -\frac{3}{2} \]
\[ \boxed{x = -\frac{3}{2}} \]