Find the Value of cos(π/7) cos(2π/7) cos(4π/7)

Question

Find the value of

\[ \cos\frac{\pi}{7}\cos\frac{2\pi}{7}\cos\frac{4\pi}{7}. \]

Solution

Use the standard identity

\[ \cos x \cos 2x \cos 4x = \frac{\sin 8x}{8\sin x}. \]

Putting

\[ x=\frac{\pi}{7}, \]

we get

\[ \cos\frac{\pi}{7}\cos\frac{2\pi}{7}\cos\frac{4\pi}{7} = \frac{\sin\frac{8\pi}{7}} {8\sin\frac{\pi}{7}}. \]

Since

\[ \sin\frac{8\pi}{7} = \sin\left(\pi+\frac{\pi}{7}\right) = -\sin\frac{\pi}{7}, \]

therefore

\[ \cos\frac{\pi}{7}\cos\frac{2\pi}{7}\cos\frac{4\pi}{7} = \frac{-\sin\frac{\pi}{7}} {8\sin\frac{\pi}{7}} = -\frac{1}{8}. \]

Answer

\[ \boxed{-\frac{1}{8}} \]

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